3x^2+1x+3x+1=96

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Solution for 3x^2+1x+3x+1=96 equation:


Simplifying
3x2 + 1x + 3x + 1 = 96

Reorder the terms:
1 + 1x + 3x + 3x2 = 96

Combine like terms: 1x + 3x = 4x
1 + 4x + 3x2 = 96

Solving
1 + 4x + 3x2 = 96

Solving for variable 'x'.

Reorder the terms:
1 + -96 + 4x + 3x2 = 96 + -96

Combine like terms: 1 + -96 = -95
-95 + 4x + 3x2 = 96 + -96

Combine like terms: 96 + -96 = 0
-95 + 4x + 3x2 = 0

Factor a trinomial.
(-19 + -3x)(5 + -1x) = 0

Subproblem 1

Set the factor '(-19 + -3x)' equal to zero and attempt to solve: Simplifying -19 + -3x = 0 Solving -19 + -3x = 0 Move all terms containing x to the left, all other terms to the right. Add '19' to each side of the equation. -19 + 19 + -3x = 0 + 19 Combine like terms: -19 + 19 = 0 0 + -3x = 0 + 19 -3x = 0 + 19 Combine like terms: 0 + 19 = 19 -3x = 19 Divide each side by '-3'. x = -6.333333333 Simplifying x = -6.333333333

Subproblem 2

Set the factor '(5 + -1x)' equal to zero and attempt to solve: Simplifying 5 + -1x = 0 Solving 5 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1x = 0 + -5 -1x = 0 + -5 Combine like terms: 0 + -5 = -5 -1x = -5 Divide each side by '-1'. x = 5 Simplifying x = 5

Solution

x = {-6.333333333, 5}

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